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JBC, Vol. 251, Issue 19, 6043-6052, Oct, 1976
W. D. Hewson and H. B. Dunford
Over a wide range of pH horseradish peroxidase compound I can be reduced
quantitatively via compound II to the native enzyme by only 1 molar
equivalent of p-cresol. Since 2 molar equivalents of electrons are required
for the single turnover of the enzymatic cycle, p-cresol behaves as a
2-electron reductant. With p-cresol and compound I in a 1:1 ratio compound
II and p-methylphenoxy radicals are obtained in the transient state.
Compound II is then reduced to the native enzyme. A possible explanation
for the facile reduction of compound II involves reaction with the
dimerization product of these radicals, 1/2 molar equivalent of
2,2'-dihydroxy-5,5'-dimethylbiphenyl. If only 1/2 molar equivalent of
p-cresol is present, than at high pH the reduction stops at compound II.
The major steady state peroxidase oxidation product of p-cresol (with
p-cresol in large excess compared to the enzyme concentration) is
Pummerer's ketone. Pummerer's ketone is only reactive at pH values greater
than about 9 where significant amounts of the enol can be formed via the
enolate anion. Therefore, in alkaline solution it is reactive with compound
I, but not with compound II, which is converted into an unreactive basic
form. These results indicate that Pummerer's ketone cannot be the
intermediate free radical product responsible for reducing compound II in
the single turnover experiments. It is postulated that Pummerer's ketone is
formed only in the steady state by the reaction of the p-methylphenoxy
radical with excess p-cresol.
Stoichiometry of the reaction between horseradish peroxidase and p-cresol
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